Serial dilution calculator

Concentration, transfer and diluent volume for every tube in a dilution series.

Series

Lowest tube

TubeConcentrationFrom stockTransfer inDiluentEnds with

What is a serial dilution?

A serial dilution is a chain of dilutions in which each tube is made from the one before it by the same factor. Ten-fold steps from a 1 M stock give 100 mM, 10 mM, 1 mM and so on; two-fold steps halve the concentration each time. Because every step reuses the previous tube, a series reaches very low concentrations with small, accurate volumes, which a single direct dilution cannot do. Standard curves, titres, MIC plates and cell counts all rely on it.

How the volumes are calculated

transfer = V ÷ f diluent = V − V ÷ f Cn = C0 ÷ fn

V is the volume each tube should hold when it is made and f is the fold per step. Every tube receives the same diluent volume, then the transfer volume from the previous tube, and is mixed before the next transfer. After n steps the concentration is the stock divided by fn, and the overall dilution is 1:fn.

Worked example. A 10-fold series of six tubes at 100 µL from a 1000 µM stock: each tube gets 90 µL of diluent and 10 µL from the tube before, so the concentrations run 100, 10, 1, 0.1, 0.01 and 0.001 µM, that is 1 nM in tube 6, an overall dilution of 1:10⁶. Total diluent is 540 µL and only 10 µL of stock is used.

Choosing the dilution factor

  • 2-fold for standard curves, IC50 and titration plates. The points are evenly spaced on a log axis and close enough to define a curve; twelve wells span three orders of magnitude. Fit the result with the ELISA analyzer or theIC50 calculator.
  • 10-fold for plate counts, phage and virus titres and anything spanning many orders of magnitude. Count the plate in the 30–300 range and convert with theCFU calculator.
  • 3- to 5-fold when you need wider spacing than 2-fold without the coarse gaps of 10-fold, for example a first-pass dose-response scan.
  • Use the target field to find how many tubes a series needs to reach a given lowest concentration; the answer is rounded up, so the last tube lands at or below the target.

Why the last tube has more volume

Each tube passes one transfer volume on to the next, so tubes 1 to n−1 end with V − V ÷ f while tube n keeps the full V. In the 10-fold example above, tubes 1–5 finish with 90 µL and tube 6 with 100 µL. If every well must hold the same volume, discard the transfer volume from the last tube. The planner shows the finishing volume of every tube so nothing is a surprise.

Pipetting accuracy in a dilution series

Errors compound: a 3 % error on each transfer becomes about 20 % after six steps. Keep transfers at 2 µL or more, preferably 10 µL or more, by choosing a larger tube volume or a smaller fold. Mix each tube fully before transferring, change tips between tubes, and pre-wet the tip for viscous or protein solutions. The planner flags any transfer below 2 µL. For a single dilution from stock to a working concentration, the C₁V₁ = C₂V₂ dilution calculator is the simpler tool.

Frequently asked questions

How do I make a 10-fold serial dilution?

Put 900 µL of diluent in each tube. Transfer 100 µL of stock into tube 1 and mix; transfer 100 µL from tube 1 into tube 2 and mix; repeat down the row. Each tube is 10× more dilute than the one before, so tube 3 is 1:1000. The planner gives the exact volumes for any fold, tube volume and number of tubes.

What is the difference between dilution factor and dilution ratio?

A dilution factor of 10 (10-fold, written 1:10) means one part sample in ten parts total, so 1 part sample plus 9 parts diluent. Some people write 1:9 to mean the same mix; check which convention a protocol uses. This planner uses the total-volume convention: a 10-fold step transfers one tenth of the tube volume.

Why does the last tube have more liquid than the others?

Every tube except the last gives up one transfer volume to the next tube. If each tube starts with V and passes on V ÷ f, it ends with V − V ÷ f while the last tube keeps the whole V. Discard the transfer volume from the last tube if all tubes need to match, or simply plan for it.

How many steps do I need to reach a target concentration?

Divide the stock by the target and take the logarithm in base f: steps = log(stock ÷ target) ÷ log(f), rounded up. From 1 mM to 1 nM in 10-fold steps needs 6 tubes. Enter a target in the planner and it works this out for you.

What is the smallest volume I should transfer?

Keep every transfer at 2 µL or more with a calibrated pipette, and ideally 10 µL or more. Below that, the error on a single pipetting step is several percent and it compounds down the series. Use a larger tube volume or a smaller fold if the planner flags a small transfer.